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-.1x^2+.6x+7=0
We add all the numbers together, and all the variables
-0.1x^2+.6x+7=0
a = -0.1; b = .6; c = +7;
Δ = b2-4ac
Δ = .62-4·(-0.1)·7
Δ = 3.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.6)-\sqrt{3.16}}{2*-0.1}=\frac{-0.6-\sqrt{3.16}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.6)+\sqrt{3.16}}{2*-0.1}=\frac{-0.6+\sqrt{3.16}}{-0.2} $
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